How do I simplify these numbers?

(2a)^3 = (2^3)*(a^3) = 8a^3
Same Way
(3x^2)^3 = 3^3 (x^2)^3= 27x^6
(2y/5x)^3 = 8y^3/125x^3

1)
(2a)^3
= (2a)(2a)(2a)
= (2^2 * a^2)(2a)
= (4a^2)(2a)
= 8a^3

2)
(3x^2)^3
= (3x^2)(3x^2)(3x^2)
= [3^2 * x^(2 + 2)](3x^2)
= (9x^4)(3x^2)
= 27x^6

3)
[2y/(5x)]^3
= [(2y)(2y)(2y)]/[(5x)(5x)(5x)]
= (8y^3)/(125x^3)

Q:
How do I simplify these numbers?
I really don't understand what to do.

(2a)^3

(3x^2)^3

(2y/5x)^3

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A: kindly see>> as below:

*** You have to separate these alphanumeric characters, to the numeric and alpha

characters, with their power number's, respectively; ok, start now:

1-Step: While the [2a)^3]=[2^3a^3= 8a^3]

2- Step: While the [(3x^2)^3] = [3^3 (x^2)^3]= [27x^6]

3-Step: While the [(2y/5x)^3] = [(2y)^3/(5x)^3 ]=

[(2^3 y^3)/(5^3 x^3)] = [8y^3/(125x^3)]

Ok

Good Lucks

A77p.

Feb.05.2010

(2a)^3 = 2^3a^3 = 8a^3

(3x^2)^3 = 3^3 (x^2)^3 = 27x^6

(2y/5x)^3 = (2y)^3/(5x)^3 = (2^3 y^3)/(5^3 x^3) = 8y^3/(125x^3)