F.4 m2 trigonometry
2010-02-06 3:13 am
It is given that tan(α+β)=m, tan(α-β)=n and mn≠1. Find the value of tan2α in terms of m and n.
回答 (1)
2010-02-06 3:21 am
✔ 最佳答案
tan2a= tan[(a+b) + (a-b)]
= [tan (a+b) + tan (a-b)] / [1 - tan(a+b) tan(a-b)]
= (m + n) / (1 - mn)
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