how can I solve this 5 x +13 < 45.?

5x + 13 < 45. Subtract 13 from both sides of the equation.

5x < 45 - 13.

5x < 32. Divide both sides by 5.

x < 32/5. Answer

12x - 8 = 3x + sixty 4 12x - 3x = sixty 4 + 8 9x = 72 x = 8 ........................... one hundred - 4x = 20 + 6x -4x - 6x = 20 - one hundred -10x = - 80 10x = 80 x = 8 ....................... 9) y = 2x - 6 open ....................... 10) genuine ...................... eleven) fake uninterested in this

5x + 13 < 45
5x < 45 - 13
x < 32/5 (6.4)

5 x < 32

x < 32/5

First subtract 13 from both sides.
5x+13<45
5x-13+13<45-13
Then, divide each side by 5.
5x<32
5x/5<32/5
Then....solve....
x<6.4

Just like a regular equation... except that if you divide by a negative number you have to reverse the inequality. So ...
5 x +13 < 45
5x < 45-13
5x < 32
x < 32/5

Much like with an equation, you can add or minus anything from an inequality:

5x < 32

Then you can multiply or divide by POSITIVE numbers.

x < 6.4

5x < 32
x < 32/5