Use logarithms to find 3^(5x-4) = 100?

3^(5x - 4) = 100
log[3^(5x - 4)] = log(100)
(5x - 4)log(3) = 2
5x - 4 = 2/log(3)
5x = 4 + 2/log(3)
x = [4 + 2/log(3)]/5
x = [4log(3)/log(3) + 2/log(3)]/5
x = [4log(3) + 2]/[log(3)](1/5)
x = [4log(3) + 2]/5log(3) (1.63836131)

(5x-4)log30=log100
5x-4=log100/log30
x=((log100/log30)+4)/5

3^(5x-4) = 100
Take logs to base 10 : (5x-4)log3=log100
0.477(5x-4)=2
5x-4=4.19, 5x=8.19, x=1.64

( 5x - 4 ) log 3 = log 100

5x - 4 = log 100 / log 3

5x = 4 + log 100 / log 3

x = [ 4 + ( log 100 / log 3 ) ] / 5

Sorry but do not gave a calculator to hand.
Any log base may be used.

log (4 • 100) = log 4 + log 100 = log 4 + 2

3^(5x-4) = 100
by using(lnm^n=nlnm)
(5x-4)ln(3)=ln100
(5x-4)(1.0986)=2
5.493x-4.3944=2
5.493x=6.3944
x=(6.3944/5.493)
x=1.1641

3^(5x-4) =100
Log3^5x-4=Log100
5x-4 =Log100/Log3
5x =Log100/Log3+4
x =Log100/Log3+4/5
x =1.6384

x=1.638361