物理physics
回答 (3)
2010-01-30 4:00 am
✔ 最佳答案
Use the formula: C = Co/2^nwhere Co is the initial count-rate
C is the count-rate at time t
n is the number of half-lives (= t/T, where T is the half-life)
Hence, 30 = 960/2^(2.5/T)
solve for T gives T = 0.5 hours
2010-01-31 4:17 am
Suppose there is no background,
980*(1/2)^n = 30
(1/2)^n=3/98
n=log(3/98)/log(1/2)
放射源的半衰期
= 2.5hr/n
= 2.5hr*log(1/2)/log(3/98)
= 0.497hrs(corr . to 3 sig.fig.)
980*(1/2)^n = 30
(1/2)^n=3/98
n=log(3/98)/log(1/2)
放射源的半衰期
= 2.5hr/n
= 2.5hr*log(1/2)/log(3/98)
= 0.497hrs(corr . to 3 sig.fig.)
2010-01-30 10:32 pm
半衰期= 0.5 hours
收錄日期: 2021-04-23 20:39:18
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