F. 2 數學_

🎓 學業台小學及中學教育

[匿名]

2010-01-27 2:03 am

80x^2 - 605 = ?
x^3 - 8x^2 +16x = ?
Factorization of Simple Polynomials

更新1:

但係第1條應該係: a^2 - b^2x = (a+b)(a+b) 而第二條就應該係: a^2 + 2ab + b^2 = (a+ b)^2 0r a^2 - 2ab + b^2 = (a- b) ^2

回答 (4)

用戶2053

2010-01-27 2:24 am

✔ 最佳答案

80x^2 - 605

= 5(16x^2 - 121)

= 5((4x)^2 - 11^2)......then using a^2 - b^2 = (a-b)(a+b)

= 5(4x - 11)(4x + 11)

x^3 - 8x^2 +16x

= x(x^2 - 8x + 16)

= x(x^2 - 2(4)(x) + 4^2) ..then using (a^2 - 2ab + b^2) = (a-b)^2

= x(x - 4)^2

👍 0 👎 0

2010-01-31 11:34 am

80x^2 - 605
= 5(16x^2 - 121)
=5(4x-11)(4x+11)

x^3 - 8x^2 +16x
= x(x^2 - 8x + 16)
=x(x-4)^2

👍 0 👎 0

[匿名]

2010-01-31 2:52 am

80x^2 - 605
= 5(16x^2 - 121)

x^3 - 8x^2 +16x
= x(x^2 - 8x + 16)

希望可以幫到你啦啦!!!

👍 0 👎 0

[匿名]

2010-01-27 2:08 am

80x^2 - 605
= 5(16x^2 - 121)

x^3 - 8x^2 +16x
= x(x^2 - 8x + 16)

👍 0 👎 0

收錄日期: 2021-04-21 22:06:56
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