Please help me with this algebra problem.?

Simplify the RHS of the equation by combining like terms.

Did you get

3x + 6 ?

Then the equation reads:

3x + 6 = 3x + 6

Does that make sense to you ?

Substitute any number for x and the statement will be true !

You have to read your text book and pay attention in class.

QED

3x + 6 = 2x + 10
3x - 2x + 6 = 10
x + 6 = 10
x = 10 - 6
x = 4

Lets try to solve for x first

3x+6=2x+10+x-4 but 2x+10+x-4 becomes 3x+6

So both sides of the equation are 3x+6

If you went further trying to solve for x everything would cancel and you would end up with 0=0

Examine 3x+6=3x+6 If you replaced both x's by the same number(no matter what number you choose) the two sides would come out the same. This is not a conditional equation where only a few numbers make it true, but an identity where all numbers make it true

PCABATS

First, they want you to plug in some numbers for x to see if the equation will be true. Try 1 and 0. They are usually the easiest.

3(1) + 6 = 2(1) + 10 + 1 -4
3 + 6 = 2 + 10 + 1 -4
9 = 9

3(0) + 6 = 2(0) + 10 + 0 - 4
6 = 6

No matter what you plug in for x, the equation is true.

Now, try solving for x. The x will go away. If the remaining equation is TRUE, then the solution is All Real Numbers. (If the remaining equation is not true, then there is No solution).

3x + 6 = 2x + 10 + x - 4 Combine like terms (simplify)
3x + 6 = 3x + 6 subtract 3x from both sides (also, notice both sides are the same)
6 = 6
True. Solution is All Real Numbers

substitute numbers for x i think is something like this.... random number in parentheses.
3(2) + 6 = 2(2) +10 + 2 - 4
12 = 12
something like that, it should work for any number (supposedly)

Let's try x = 1.

3(1) + 6 = 2(1) + 10 + 1 - 4
3 + 6 = 2 + 10 + 1 - 4
9 = 9

This will work, no matter what number(s) you use.

3x + 6 = 2x + 10 + x - 4
3x + 6 = 3x + 6
This is an identity.