將一塊0.1 kg 、溫度為0 ° c 的冰塊放入1 kg
溫度為60 ° c 的水中。假設並沒有熱量散失
到周圍環境中，問混合物的末溫度是多少？
a. 46.7 ° c
B. 47.3 ° c
c. 52.3 ° c
D. 54.5 ° c
*唔該列式
物理唔識?about 熱學....
2010-01-20 4:26 am
回答 (2)
2010-01-20 5:03 am
✔ 最佳答案
水的比熱容量=4200jkg-1C-1冰的熔解比潛熱=3.34x10 5次方Jkg-1
設T為混和後的溫度。
水的能量損失=冰塊的能量增加
(1)x(4200)x(60-T)=(0.1)x(3.34x10^5)+(0.1)(4200)(T-0)
熔解過程中獲 溫度增加過程中獲
得的能量 得的能量
252000-4200T=33400+420T
218600=4620T
T=47.316.....(47.3C)
希望你能明白過程^^
參考: 自己所學
2010-01-20 4:42 am
Heat absorbed by ice = 0.1 x (334000 + 4200 xT) J
where T is the final temperature of the mixture
Heat given out by water = 1 x 4200 x (60-T) J
Since there is no heat lost to the surroundings
0.1 x (334000 + 4200 xT) = 1 x 4200 x (60-T)
solve for T gives T = 47.3'C
where T is the final temperature of the mixture
Heat given out by water = 1 x 4200 x (60-T) J
Since there is no heat lost to the surroundings
0.1 x (334000 + 4200 xT) = 1 x 4200 x (60-T)
solve for T gives T = 47.3'C
收錄日期: 2021-04-29 17:32:49
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