Please Factor 2z^2+5z-18?
回答 (8)
2010-01-17 9:43 am
✔ 最佳答案
2z² + 5z - 18 = 02z² + 5z = 18
z² + 5/2z = 9
z² + 5/4z = 9 + (5/4)²
z² + 5/4z = 144/16 + 25/16
(z + 5/4)² = 169/16
z + 5/4 = ± 13/4
Factors (horizontally presented):
= z + 5/4 - 13/4, = z - 8/4, = z - 2
= z + 5/4 + 13/4, = z + 18/4, = z + 9/2, = 2z + 9
Answer: (z - 2)(2z + 9)
2010-01-17 5:26 pm
2z^2+5z-18
=(2z+9)(z-2) answer//
=(2z+9)(z-2) answer//
2010-01-17 4:49 pm
= 2z^2 + 5z - 18
= 2z^2 + 9z - 4z - 18
= 2z(z-2) + 9(z-2)
= (z-2)(2z+9)
= 2z^2 + 9z - 4z - 18
= 2z(z-2) + 9(z-2)
= (z-2)(2z+9)
2010-01-17 4:46 pm
= 2z^2 + 5z - 18
= 2z^2 + 9z - 4z - 18
= 2z(z-2) + 9(z-2)
= (z-2)(2z+9)
= 2z^2 + 9z - 4z - 18
= 2z(z-2) + 9(z-2)
= (z-2)(2z+9)
2010-01-17 4:46 pm
2z^2+5z-18
= (2z + 9)(z - 2 )
= (2z + 9)(z - 2 )
2010-01-17 4:45 pm
2z² + 5z - 18 = (2z + 9)(z - 2)
2010-01-17 4:46 pm
2z^2 = 2z*z
-18 = 9*-2
9*z+(-2)*2z=5z
Put everything together and you'll get the answer.
-18 = 9*-2
9*z+(-2)*2z=5z
Put everything together and you'll get the answer.
2010-01-17 6:57 pm
2z^2 + 5z - 18
= 2z^2 + 9z - 4z - 18
= (2z^2 + 9z) - (4z + 18)
= z(2z + 9) - 2(2z + 9)
= (2z + 9)(z - 2)
= 2z^2 + 9z - 4z - 18
= (2z^2 + 9z) - (4z + 18)
= z(2z + 9) - 2(2z + 9)
= (2z + 9)(z - 2)
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