the half-life ( t 1/2 ) of a first-order reaction is given by ( t 1/2 ) = ln 2/k . In a
first-order decomposition reaction, 25.0% of reactant would remain after 30.0
min. what is the rate constant(k) of the reaction?
half-life question
2010-01-18 5:38 am
回答 (1)
2010-01-18 6:05 am
✔ 最佳答案
Let n be the number of half-lives.(1/2)^n = 25%
n = 2
Half-live, t1/2 = 30 / 2 = 15 min
t1/2 = ln2 / k
k = ln2 / 15
rate constant, k = 0.0462 min^-1
參考: 老爺子
收錄日期: 2021-05-01 01:01:18
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