(log x^4 + log y^2) / log x y^ (1/2)
=?
Ans: 4
What are the steps?
F4 Maths (Log) Quickly please!
2010-01-18 1:23 am
回答 (2)
2010-01-18 1:29 am
✔ 最佳答案
(log x^4 + log y^2) / log x y^ (1/2)= (4log x + 2log y) / (log x + log y^(1/2))
= (4log x + 2log y) / (log x + (1/2)log y)
= 2(2log x + logy) / (1/2) (2log x + log y)
= 2 / (1/2)
= 4
2010-01-18 1:43 am
(log x^4 + log y^2) / log x y^ (1/2)
=(4logx+2logy)/(logx+1/2logy)
=2(2logx+logy)/(logx+1/2logy)
=2(2logx+logy)/1/2(2logx+logy)
=2/(1/2)
=4
=(4logx+2logy)/(logx+1/2logy)
=2(2logx+logy)/(logx+1/2logy)
=2(2logx+logy)/1/2(2logx+logy)
=2/(1/2)
=4
參考: me
收錄日期: 2021-04-21 22:07:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100117000051KK01024