[(2x+3)/5] – [(3x-1)/3] = [(x-1)/15]?

(2x - 3) / 5 - (3x - 1) / 3 = (x - 1) / 15

Multiplying every term by 15, we have:

3(2x - 3) - 5(3x - 1) = x - 1

Multiplying out the brackets:

6x - 9 - 15x + 5 = x - 1

Collection all the x terms on the right hand side and all the constant terms on the left hand side:

10x = 15

So x = 3/2 = 1.5.

6x + 9 - 15x + 5 = x - 1

15 = 10 x

x = 3/2

{(2x + 3)/5} - {(3x - 1)/3} = {(x -1)/15}
{(15/1)(2x + 3)/5} - {(15/1)(3x - 1)/3} = {(15/1)(x - 1)/15}
{3(2x + 3)} - {(5)( 3x - 1)} = (x - 1)
(6x + 9) - (15x - 5) = x - 1
6x + 9 - 15x + 5 = x - 1
- 9x + 14 = x - 1
-10x = - 15
x = 3/2 or 1 1/2 or 1.5.

3(2x+3) -5(3x-1)/15 = 6x+ 9 -15x +5/15

= - 9x + 14/15
= 14 - 9x/15

(2x + 3)/5 - (3x - 1)/3 = (x - 1)/15
15[(2x + 3)/5 - (3x - 1)/3] = 15[(x - 1)/15]
3(2x + 3) - 5(3x - 1) = x - 1
3(2x) + 3(3) - 5(3x) - 5(-1) = x - 1
6x + 9 - 15x + 5 = x - 1
6x - 15x - x = -9 - 5 - 1
-10x = -15
x = -15/(-10)
x = 3/2 (1.5)