求數學高手幫幫忙!

2010-01-16 11:53 pm
Find the H.C.F and L.C.M of (x+1)^2(x-1)^2 and (x+1)(x-1)

回答 (3)

2010-01-17 12:01 am
✔ 最佳答案
H.C.F is 1
L.C.M is (x+1)^2(x-1)^2

2010-01-16 16:03:02 補充:
if there is a comma between (x+1)^2 and (x-1)^2
then H.C.F. will be (x+1)(x-1)

2010-01-16 16:04:06 補充:
if there is not a comma between (x+1)^2 and (x-1)^2
then H.C.F. will be (x+1)(x-1)

2010-01-18 20:48:27 補充:
不用理我的,deathnotesimonxdd,因為我有一些東西打錯了。
參考: myself, me, me
2010-01-17 12:07 am
if there is a comma between (x+1)^2 and (x-1)^2
then H.C.F. will be (x+1)(x-1) ???
唔係好明...
例如(x+1)^2,(x-1)^2 and (x+1)(x-1) 的 H.C.F.
才是1嗎???
(x+1)^2(x-1)^2 and (x+1)(x-1)的H.C.F.(最大公因數)
不是(x+1)(x-1)嗎???1是公因數,,,卻不是最大的
2010-01-16 11:58 pm
(x+1)^2(x-1)^2=[(x+1)(x-1)]^2
H.C.F=(x+1)(x-1)
L.C.M=(x+1)^2(x-1)^2
參考: 自己


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