(x-2)^2-16 QUADRATICS?

(x-2)^2-16 = ((x-2) + 4)((x-2) - 4)
= (x + 2) (x - 6)
= x^2 - 4x - 12

Factor completely:
(x - 2)^2 - 16
= (x - 2)^2 - 4^2
= [(x - 2) + 4][(x - 2) - 4]
= (x - 2 + 4)(x - 2 - 4)
= (x + 2)(x - 6)

(x-2)^2 ..................formula (a-b)^2 = a^2 - 2ab +b^2
=x^2 +4x + 4
=x^2 +4x + 4 - 16
=x^2 +4x -12
=x^2 +6x -2x -12
=x(x+6) -2(x+6)
=(x+6)(x-2)

[ ( x - 2 ) - 4 ] [ ( x - 2 ) + 4 ]

( x - 6 ) ( x + 2 )

What exactly is the question ?