How do i do this log problem in maths ?

let log be log to base 2

1+ 2 log x = 5

2 log x = 4

log x = 2

x = 2 ²

x = 4

1 + 2log_2(x) = 5
2log_2(x) = 5 - 1
log_2(x) = 4/2
x = 2^2
x = 4

1 + 2log_2(x) = 5

2log_2(x) = 4

log_2(x) = 2

2^2 = x

==> x = 4

1 + 2log₂ x = 5
2log₂ x = 4
log₂ x = 2
x = 2²
x = 4

1+2log_2(X) = 5

2log_2(x) = 4

log_2(x²) = 4

2^4 = x²

16 = x²

x = ±√16

x = ±4

But reject -4 as a solution as it would cause a negative log in the original equation.

Solution is x = 4

Have a good day!

You pay attention in class and ask your tutor when you get stuck.