Express 120 as a product of its prime factors?

120 = 2 x 2 x 2 x 3 x 5
or
120 = 2^3 x 3 x 5

The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12. 15, 20. 24, 30, 40, 60 and 120.

120 = 2 x 2 x 2 x 3 x 5

Prime factors of 120: 2^3 • 3 • 5

120=2x2x2x3x5 prime factorization

2*2*2*3*5*

10 x 12

2 x 5 x 2 x 6

2 x 2 x 2 x 3 x 5

2 ³ x 3 x 5

12 x 10 4 x 3 x 2 x 5 2³ x 3 x 5

Any one know the answer to

express 120 as the product of prowess of its prime factors

This is the kind of problem in which a "prime factor tree" helps a lot.

Start with 120, then choose two numbers that multiply to get 120. Then keep breaking down each number until you can go no further. The product of those final numbers is your answer.

For example:

120 --> 3 X 40
You can't go any further with 3, so that is one of its prime factors.
Keep going with 40.

40 --> 4 X 10
Keep going with both of these.

4 --> 2 X 2 (done)
10 --> 5 X 2 (done)

Looking at all your final numbers, which are all prime, you have:
120 = 3 X 2 X 2 X 2 X 5

The convention is to put them in order to get:
2 X 2 X 2 X 3 X 5 OR 2^3 X 3 X 5

Sieve method is ideal

divide 120 by 2 giving 60, so 2 is a factor
divide 60 by 2 giving 30, so 2 is again a factor
divide 30 by 2 giving 15, so 2 is again a factor
but 15 is not divisible by 2, and you don't need to test any more EVEN numbers
15 is divisible by 3 giving 5, and so 3 is also a factor
5 is not divisible by 3, so try the next odd number which is 5
5 is divisible by 5, so 5 is a factor
(normally you continue this process until the number you are trying squared is greater than what you are testing)
the factors are 2^3, 3, 5

The lowest prime number is 2
120 = 2 * 60 = 2^2 * 30 = 2^3 * 15
But 15 does not divide by 2

The next prime number is 3
120 = 2 * 60 = 2^2 * 30 = 2^3 * 15 = 2^3 * 3 * 5
This is a product of prime numbers