gravi. energy derivation

2010-01-13 8:26 am
As the gravitational potential energy is defined as
negative work done by the gravitational force in bringing the point from infinity to that point,



圖片參考:http://i256.photobucket.com/albums/hh182/zilu_photo/sshot-2010-01-13-00-25-39.png
更新1:

(-GMm/r^2).dr how do you explain this? in geometry, i think this is positive as they are in the same direction (the dot product of two vectors)

更新2:

however in physics i know this is negative as there is an external force to keep the KE of the body constant. so gravity does negative work in bringing the body to that point i am confused at the beginning - defining the sign of dW

回答 (1)

2010-01-13 10:17 pm
✔ 最佳答案
dU = -dW = -[(-GMm/r^2).dr]
U = -W = - integrate[infinity --> r]{(-GMm/r^2).dr} = -[infinity --> r]{GMm/r}
= -GMm/r

The work done refers to that done by the gravitational force.


收錄日期: 2021-04-29 17:34:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100113000051KK00049

檢視 Wayback Machine 備份