1)given f(x)=1/x and g(x)=x^2, i)find f(1/3)+g(-2), ii)find g{f(2)}.
2)solve the following equation: 2^2x+6=4^5-x.
數學問題 請幫手
2010-01-13 6:13 am
回答 (1)
2010-01-13 6:20 am
✔ 最佳答案
1)i) f(1/3)+g(-2)= 1/(1/3) + (-2)^2
= 3 + 4
= 7
ii) g{f(2)}
= [f(2)]^2
= (1/2)^2
= 1/4
2)2^2x+6=4^5-x
2^(2x+6) = 4^(5-x)
2^(2x+6) = 2^2(5-x)
2x+6 = 2(5-x)
2x+6 = 10 - 2x
4x = 10 - 6
x = 1
收錄日期: 2021-04-21 22:06:53
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100112000051KK01635