maths~~~~~~~~~~~

2010-01-12 5:54 am

回答 (1)

2010-01-12 6:06 am
✔ 最佳答案
AD / / EG // BC ,
AE / EB = AF/FC = DG / GC
2/2 = (2x - 1)/3y = (3x - 5) / (2y - 1)
2x - 1 = 3y...(1) and 3x - 5 = 2y - 1...(2)
(1)*3 - (2)*2 :
- 3 - (-10) = 9y - (4y - 2)
7 = 5y + 2
y = 1
x = 2


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