Algebra 2; Factoring by grouping x^3+x^2+x+1?
回答 (4)
2010-01-10 9:39 pm
✔ 最佳答案
x³ + x² + x + 1 = x²(x + 1) + (x + 1) =
(x + 1)(x² + 1)
2010-01-14 5:10 am
x^3 +x^2 +x +1 = 0
Separate : ( x^3 +x^2 ) + ( x +1 ) = 0
Commutative Law : ( x^3 +x ) + ( x^2 +1 ) = 0
Distributive Law : x*( x^2 +1 ) + +*( x^2 +1 ) = 0
Factor : ( x +1 )*( x^2 +1 ) = 0
Separate : ( x^3 +x^2 ) + ( x +1 ) = 0
Commutative Law : ( x^3 +x ) + ( x^2 +1 ) = 0
Distributive Law : x*( x^2 +1 ) + +*( x^2 +1 ) = 0
Factor : ( x +1 )*( x^2 +1 ) = 0
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2010-01-10 10:34 pm
x ² ( x + 1 ) + ( x + 1 )
( x + 1 ) ( x ² + 1 )
( x + 1 ) ( x ² + 1 )
2010-01-10 9:38 pm
Take an x^2 from the first two terms. Now you have (x + 1) as a common term. Factor it out.
x^2(x + 1) + (x + 1) =
(x^2 + 1)(x + 1)
x^2(x + 1) + (x + 1) =
(x^2 + 1)(x + 1)
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