How do you factor 20x^2=9x+18? pleaseee help!?
回答 (6)
2010-01-10 7:36 am
✔ 最佳答案
Use the Quadratic formula. I'm too lazy to see if it actually factors or not, but the the quadform always does the job.[-b (+-) sqrt(b^2 - 4ac)] / 2a
2010-01-10 3:42 pm
20 x^2 = 9x + 18
20 x^2 - 9x -18 = 0
20 x^2 + 15x - 24x -18 = 0
5x(4x+3) - 6(4x+3) = 0
( 4x+3 ) ( 5x - 6 ) = 0
so
4x + 3 = 0 or 5x - 6 = 0
x = -3/4 or x = 6/5
20 x^2 - 9x -18 = 0
20 x^2 + 15x - 24x -18 = 0
5x(4x+3) - 6(4x+3) = 0
( 4x+3 ) ( 5x - 6 ) = 0
so
4x + 3 = 0 or 5x - 6 = 0
x = -3/4 or x = 6/5
2010-01-10 3:47 pm
20x^2=9x+18
20x^2-9x-18=0
(4 x+3) (5 x-6)=0
4x+3=0 5x-6=0
4x=-3 5x=6
x=-3/4 x=6/5
x=-3/4,6/5 answer//
20x^2-9x-18=0
(4 x+3) (5 x-6)=0
4x+3=0 5x-6=0
4x=-3 5x=6
x=-3/4 x=6/5
x=-3/4,6/5 answer//
2010-01-10 3:37 pm
20x^2 - 9x - 18 = 0
20x^2 - 24x + 15x - 18 = 0
4x(5x -6) + 3(5x -6) = 0
(4x+3)(5x-6) = 0
If solving for x, then x = -3/4 or x = 6/5
20x^2 - 24x + 15x - 18 = 0
4x(5x -6) + 3(5x -6) = 0
(4x+3)(5x-6) = 0
If solving for x, then x = -3/4 or x = 6/5
2010-01-10 3:37 pm
20x^2 = 9x + 18
20x^2 - 9x - 18 = 0
20x^2 + 15x - 24x - 18 = 0
(20x^2 + 15x) - (24x + 18) = 0
5x(4x + 3) - 6(4x + 3) = 0
(4x + 3)(5x - 6) = 0
20x^2 - 9x - 18 = 0
20x^2 + 15x - 24x - 18 = 0
(20x^2 + 15x) - (24x + 18) = 0
5x(4x + 3) - 6(4x + 3) = 0
(4x + 3)(5x - 6) = 0
2010-01-10 3:37 pm
first rearrange
20x^2=9x+18
20x^2-9x-18=0
(4x+3)(5x-6)=0
4x+3=0
x= -3/4
5x-6=0
x= 6/5
20x^2=9x+18
20x^2-9x-18=0
(4x+3)(5x-6)=0
4x+3=0
x= -3/4
5x-6=0
x= 6/5
收錄日期: 2021-05-01 13:00:38
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