✔ 最佳答案
Let's do a simple calculation
Assume the piece of paper is of 10 g (=0.01 kg) mass, area 10 x 10 cm^2 (= 0.01 m^2), with specific heat capacity = 1400 J/kg-K
Further assume that 90% of the power consumed by the light bulb turns into radiant heat and which is emitted equally in all directions.
Heat given out in 24 hours
= 100 x 0.9 x 24 x 3600 J = 7 776 000 J
If the piece of paper is ta distance of 10 cm (=0.1 m) from the bulb, thermal energy received by the paper
= 7776000 x 0.01/(4 x pi x 0.1^2) J = 619 000 J
If initial temperature of paper = 23'C
temperature rise of paper = 619000/(0.01 x 1400) 'C = 44,000'C
The ignition temperature of paper is only 218'C. Hence, in theory, the paper would well be on fire.
However, the calculated result may probably not happen, as once the temperature of the paper rises, heat loss to the surroundings would also take place. The higher the temperature of the paper, the higher is the rate of jeat loss. Therefore, unless the surrounding air temperature also rises to hundreds of degrees, the paper could be on fire. But given the power of a 100w light bulb, it is hard to believe that it could heat up the air inside a small room up to hundreds of degrees
At a steady air temperature of 53'C quoted in your question, the paper temperature is far below than its ignition temperature. The paper would not catch fire.
Data on specific heat capacity and ignition temperature of paper can be found from the web-pages below:
http://www.engineeringtoolbox.com/specific-heat-solids-d_154.html
http://en.wikipedia.org/wiki/Autoignition_temperature