Maths question

👨🏻‍🏫 學術台數學

卓軒

2010-01-08 5:08 am

z/ 2s-1 = 1 / 3s + 2 Change subject to s

Full step please

回答 (4)

用戶7639

2010-01-08 5:19 am

✔ 最佳答案

z / (2s - 1) = 1 / (3s + 2)
(2s-1)/z=(3s+2)
2s-1=3sz+2z
2s-3sz=2z+1
s(2-3z)=2z+1
s=(2z+1)/(2-3z)

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魔龍帝齊格益力多

2010-01-09 12:57 am

z/ 2s-1 = 1 / 3s + 2
2s-1 =3sz+2z
2s-3sz =1+2z
s(2-3z) =1+2z
s=1+2z/2-3z

2010-01-08 16:59:01 補充：
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卓軒

2010-01-08 5:12 am

yesarsssssssss

2010-01-07 21:13:12 補充：
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用戶9112

2010-01-08 5:11 am

Is it z / (2s - 1) = 1 / (3s + 2)???

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