F.4 log
回答 (2)
2010-01-08 4:54 am
✔ 最佳答案
log8x^2/log2x=log[2*(2x)^2]/log2x
=(log2+2log2x)/log2x
=log2/log2x + 2
2010-01-08 5:40 am
I assume the numbers 8 and 2 are the base of logarithm??
log_8 x^2 / log_2 x
= (logx^2 / log8) / (logx / log2)
= (2log x / 3log2) / (logx / log2)
= 2/3
log_8 x^2 / log_2 x
= (logx^2 / log8) / (logx / log2)
= (2log x / 3log2) / (logx / log2)
= 2/3
收錄日期: 2021-04-23 23:24:00
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https://hk.answers.yahoo.com/question/index?qid=20100107000051KK01390