It is given that y=k(tx+2) where t is a non constant , y=10 when x=1 and y=28
when x=4.
a)find the value of t
b)express y in terms of x
f4 variations急~!!!!!
2010-01-07 5:45 am
回答 (1)
2010-01-07 5:52 am
✔ 最佳答案
(a) y = k(tx + 2)10 = k(t + 2) ... (1)
28 = k(4t + 2) ... (2)
(1)/(2) => 10/28 = (t + 2)/(4t + 2)
10(4t + 2) = 28(t + 2)
40t + 20 = 28t + 56
12t = 36
t = 3
(b) Sub into (1), 10 = k(3 + 2) => k = 2
y = 2(3x + 2)
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