[ 數學 ]雞兔同籠

2010-01-06 7:17 am
有若干隻雞和兔,有35個頭,94隻腳.雞和兔各有幾隻?
更新1:

有若干隻雞和兔,有100個頭,316隻腳.雞和兔各有幾隻? 第一題答案:設兔有X隻,則雞有(35-X)隻. 4X+2(35-X)=94 4X+70-2X=94 4X-2X=94-70 2X=24 X=12 兔有12隻,雞有23隻.

回答 (4)

2010-01-14 4:25 am
✔ 最佳答案
設兔有y隻,則雞有(100-y)隻
4y+2(100-y)=316
4y+200-2y=316
4y-2y=316-200
2y=116
y=116除2(約簡)
y=58
答:兔有58隻,雞有100-58=42隻
參考: 我
2010-01-07 1:56 am
Let the number of the chicken be X , the number of the rabbits be Y

X+Y= 35 --------- (1)
2X+4Y= 94 -------(2)

(1) X 2

2X+2Y = 70 --------(3)

(2) - (3)

(2X-2X) + (4Y-2Y) = 94 - 70
2Y = 24
Y = 12
Sub Y = 12 into (1)

X+12 = 35
X = 23

So the number of the chicken and the rabbits are 23 and 12 respectively.
(please used three dots to represent 'so' and you should know it)

This is the method of elimination.

I don't use the method of substitution to caculate it because it is more complicated. I hope that I can help you.

2010-01-06 17:58:48 補充:
Oh, sorry that the method of substitution is also easy to caculate you can either choose the method from jasmin_1110 or from me. It's also correct. This just depends on what method do you want to use.
參考: My brain, My brain
2010-01-07 12:13 am
兔=(94-2*35)/(4-2)=12
雞=35-12=23
2010-01-06 7:37 am
雞=X
兔=Y

X+Y=35...........(1)
2X+4Y=94........(2)

(1)
X=35-Y

IF X=35-Y,
(2)
2(35-Y)+4Y=94
70-2Y+4Y=94
2Y=24
Y=12

Y=12
(1)
X+12=35
X=23

SO 雞23隻, 兔12隻


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