誰能教我這題數:
4y^2+4y-3=0
All Step
PLZ
4y^2+4y-3=0
2010-01-06 6:48 am
回答 (3)
2010-01-06 6:53 am
✔ 最佳答案
4y^2 + 4y - 3 = 04y^2 - 2y + 6y - 3 = 0
2y(2y - 1) + 3(2y - 1) = 0
(2y + 3)(2y - 1) = 0
2y + 3 = 0 or 2y - 1 = 0
y = -3/2 or y = 1/2
2010-01-07 5:12 am
Solve the quadratic equation?
By quadratic formula,
y = { -4 +/- √[4^2 - 4(4)(-3)] } / 2(4)
= (-4 +/- √64) / 8
= (-4+8) / 8 or (-4-8) / 8
= 1/2 or -3/2
By quadratic formula,
y = { -4 +/- √[4^2 - 4(4)(-3)] } / 2(4)
= (-4 +/- √64) / 8
= (-4+8) / 8 or (-4-8) / 8
= 1/2 or -3/2
2010-01-06 6:53 am
4y^2+4y-3=0
(2y-1)(2y+3)
2010-01-05 22:54:59 補充：
y=1/2 . y= -3/2
(2y-1)(2y+3)
2010-01-05 22:54:59 補充：
y=1/2 . y= -3/2
收錄日期: 2021-04-19 21:06:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100105000051KK01860