數學因式分解有D唔識

a) ab+bc+2a+2c

= b(a+c)+2(a+c)
=(a+c)(b+2)

b) 5xy-10x+4y-8 (唔知你是否打多個z,所以當冇z計)

=5x(y-2)+4(y-2)
=(y-2)(5x+4)

* 如果你冇打錯 :
=5(y-2z)+4(y-2) (冇得計了)

c) mp^2+2m+np^2+2n

=m(p^2+2)+n(p^2+2)
=(p^2+2)(m+n)

ab+bc+2a+2c
b(a+c)+2(a+c)
(b+2)(a+c)

5xy-10xz+4y-8
5x(y-2z)+4(y-2)
你係唔係打錯??

mp2+2m+np2+2n
(mp2+np2)+(2m+2n)
p2(m+n)+2(m+n)
(p2+2)(m+n)

(a) ab+bc+2a+2c
=b(a+c)+2(a+c)
=(a+c)(b+2)

(b)5xy-10xz+4y-8
=5x(y-2z)+4(y-2)
點解多咗個z既?!
如果係咁就不能分解架啦.
如果冇z個答案係:
=(y-2)(5x+4)

(c)mp^2 +2m+np^2+2n
=m (p^2 + 2 ) + n (p^2 + 2 )
=(p^2 + 2 )(m+n)

(a.)ab+bc+2a+2c

=b(a+c)+2(a+c)

=(b+2)(a+c)

(b.)5xy-10xz+4y-8

=5x(y-2z)+4(y-2) -------------- 因為 同類項 (y-2z) 和 (y-2) 不相同，所以這個就是答案。

(c.)mp^2+2m+np^2+2n

=p^2(m+n)+2(m+n)

=(p^2+2)(m+n)

希望幫倒你啦！

(a) ab+bc+2a+2c=

A. ab+bc+2a+2c
= b(a+c)+2(a+c)
= (a+c)(b+2)

(b) 5xy-10xz+4y-8=

A. 5xy-10xz+4y-8
= 5x(y-2z)+4(y-2)-----------------Cannot be further factorized. (Problems in question?)

(c) mp二次 +2m+np二次+2n=

A. mp^2+2m+np^2+2n
= m(p^2+2)+n(p^2+2)
= (p^2+2)(m+n)