F.1 Maths (Urgent, for Exam)

2010-01-04 12:21 am
Find the nth term of the following sequences -

a) 1, 5, 9, 13, 17, ......
nth term =

b) 4, 12, 36, 108, 324, ......
nth term =

c) 1, 3, 6, 10, 15, ......
nth term =

d) 4, 16, 36, 64, 100, ......
nth term =

就快考試, 可唔可以教我和解釋一下怎樣做. 十分之謝謝.

回答 (2)

2010-01-04 1:19 am
✔ 最佳答案
a) 1, 5, 9, 13, 17, ......(1,1+4,1+4+4,1+4+4+4,……….)
nth term =1+4(n-1)=4n-3
代式,a+d(n-1),a為首項,d為公差,n為項數

b) 4, 12, 36, 108, 324, ......(4x3,4x3x3,4x3x3x3,…….)
nth term =4(3)^(n-1)
代式,aR^(n-1),a為首項,d為公比,n為項數

c) 1, 3, 6, 10, 15, ......
nth term =n(1+n)/2
諗下個模式1,1+2,1+2+3,1+2+3+4,…………..
你會諗到你項數和黎

d) 4, 16, 36, 64, 100, ......(2^2,4^2,6^2,…………..)
nth term =[2+2(n-1)]^2=4n^2
睇下個模式,都係,2,4,6,8,10…………….
用番a)部我俾你果條式代入去就做到


2010-01-03 17:21:17 補充:
第一個人答d答案有好多都係錯,(a,b,d)都係錯

2010-01-03 17:50:19 補充:
第一個人改左之後既a,d部就岩啦

2010-01-04 10:07:25 補充:
希望可以幫到你啦
參考: MYSELF
2010-01-04 1:02 am
a)
nth term=8n-7

b)
nth=4(3)n-1

c)
nth=1/2 n(n+1)

d)
nth=4nn

2010-01-03 17:20:04 補充:
d)

nth=4n^2

2010-01-03 17:21:27 補充:
a)

nth term=4n-3


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