differetial equation

y - (3/2)(dy/dx) = 6
2y - 3(dy/dx) = 12
2y - 12 = 3(dy/dx)
dx = 3dy/(2y - 12)
S dx = 3 S dy/(2y - 12)
x = 3ln(2y - 12)/2 + C
2x = 3ln(2y - 12) + ln c = lnK(2y - 12)^3
so K(2y - 12)^3 = e^(2x).
or A(y - 6)^3 = e^(2x).
C, K and A are constants.

2010-01-02 18:02:10 補充：
Note: ln c = 2C which is also a constant. K = c. 8K = A.