1.4p^2-16p+16
2.3ac-3bc+4a-4b
3.x^2+26x+169
4.4x^2+4xy+y^2
5.x^2-18x+81
列埋steps唔該
f.2簡單factorization
2010-01-02 3:46 am
回答 (4)
2010-01-02 3:51 am
✔ 最佳答案
1.4p2-16p+16=4(p2-4p+4)
=4(p-2)2
2.3ac-3bc+4a-4b
=3c(a-b)+4(a-b)
=(a-b)(3c+4)
3.x2+26x+169
=(x+13)2
4.4x2+4xy+y2
=(2x+y)2
5.x2-18x+81
=(x-9)2
2010-01-02 10:28 pm
1)4p^2-16p+16
=4(p2-4p+4)
=4(p-2)2
2)3ac-3bc+4a-4b
=3c(a-b)+4a(a-b)
=(3c+4a)(a-b)
3)x^2+26x+169
=(x+13)2
4)4x^2+4xy+y^2
=(2x+y)2
5)x^2-18x+81
=(x-9)2
2010-01-02 14:30:59 補充：
第二條打錯,3ac-3bc+4a-4b
=3c(a-b)+4(a-b)
=(3c+4)(a-b)
=4(p2-4p+4)
=4(p-2)2
2)3ac-3bc+4a-4b
=3c(a-b)+4a(a-b)
=(3c+4a)(a-b)
3)x^2+26x+169
=(x+13)2
4)4x^2+4xy+y^2
=(2x+y)2
5)x^2-18x+81
=(x-9)2
2010-01-02 14:30:59 補充：
第二條打錯,3ac-3bc+4a-4b
=3c(a-b)+4(a-b)
=(3c+4)(a-b)
參考: me
2010-01-02 9:53 pm
1.4p^2-16p+16
= 4(p^2-4p+4)
= 4(p-2)^2
2.3ac-3bc+4a-4b
= 3c(a-b)+4(a-b)
=(3c+4)(a-b)
3.x^2+26x+169
= (x+13)^2
4.4x^2+4xy+y^2
= (2x+y)^2
5.x^2-18x+81
= (x+9)^2
= 4(p^2-4p+4)
= 4(p-2)^2
2.3ac-3bc+4a-4b
= 3c(a-b)+4(a-b)
=(3c+4)(a-b)
3.x^2+26x+169
= (x+13)^2
4.4x^2+4xy+y^2
= (2x+y)^2
5.x^2-18x+81
= (x+9)^2
2010-01-02 9:36 am
以下的數除了第二條外,全部都可以利用方程式的計法,
即a^2+2ab+b^2 = (a+b)^2 或 a^2-2ab+b^2 = (a-b)^2
1.4p2-16p+16 (即用(a-b)^2)
=(2p-4)^2
2.3ac-3bc+4a-4b
=3c(a-b)+4(a-b)
=(a-b)(3c+4)
3.x^2+26x+169 (即用(a+b)^2)
=(x+13)^2
4.4x^2+4xy+y2 (即用(a+b)^2)
=(2x+y)^2
5.x^2-18x+81 (即用(a-b)^2)
=(x-9)^2
即a^2+2ab+b^2 = (a+b)^2 或 a^2-2ab+b^2 = (a-b)^2
1.4p2-16p+16 (即用(a-b)^2)
=(2p-4)^2
2.3ac-3bc+4a-4b
=3c(a-b)+4(a-b)
=(a-b)(3c+4)
3.x^2+26x+169 (即用(a+b)^2)
=(x+13)^2
4.4x^2+4xy+y2 (即用(a+b)^2)
=(2x+y)^2
5.x^2-18x+81 (即用(a-b)^2)
=(x-9)^2
收錄日期: 2021-04-13 17:00:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20100101000051KK03220