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Factorise 32 - u^5 please?
回答 (8)
2009-12-30 11:27 am
✔ 最佳答案
32 - u^5=-(u-2) (u^4+2 u^3+4 u^2+8 u+16) answer//
2016-12-18 12:54 am
until now initiate the question you may desire to undergo in ideas a formula and that's a million)a^2 - b^2=(a + b) (a - b) now,flow on your question Q.2y^2 - 32 take 2 as uncomplicated =>2(y^2 - sixteen) =>2{(y)^2 - (4)^2} =>2(y + 4) (y - 4)
2009-12-30 11:18 am
we know :
a^n - b^n = (a-b).( a^(n-1) + a^(n-2).b +...+a.b^(n-2) + b^(n-1) )
so we have
32-u^5=2^5-u^5=(2-u)(16+8u+4u^2+2u^3+u^4)
a^n - b^n = (a-b).( a^(n-1) + a^(n-2).b +...+a.b^(n-2) + b^(n-1) )
so we have
32-u^5=2^5-u^5=(2-u)(16+8u+4u^2+2u^3+u^4)
2009-12-30 11:12 am
32 - u^5
= 2^5 - u^5
= (2 - u)(2^4 + 2^3.u + 2^2.u^2 + 2.u^3 + u^4)
= (2 - u)(16 + 8u + 4u^2 + 2u^3 + u^4)
. . . . . . . . . . A N S W E R . . . . . . .. . . . .
= 2^5 - u^5
= (2 - u)(2^4 + 2^3.u + 2^2.u^2 + 2.u^3 + u^4)
= (2 - u)(16 + 8u + 4u^2 + 2u^3 + u^4)
. . . . . . . . . . A N S W E R . . . . . . .. . . . .
2009-12-30 11:11 am
32 - u^5
2^5 - u^5=(2-u)(16+8u+4u²+2u³+u^4)
2^5 - u^5=(2-u)(16+8u+4u²+2u³+u^4)
2009-12-30 11:11 am
32 - u^5
= 2^5 - u^5
= (2-u)(u^4+2u^3+4u^2+8u+16)
= 2^5 - u^5
= (2-u)(u^4+2u^3+4u^2+8u+16)
2009-12-30 11:08 am
32 - u^5
= 2^5 - u^5
= (2 - u)(16 + 8u + 4u^2 + 2u^3 + u^4)
= 2^5 - u^5
= (2 - u)(16 + 8u + 4u^2 + 2u^3 + u^4)
2009-12-30 11:04 am
32-u^5
(2)^5-u^5
(2)^5-u^5
收錄日期: 2021-05-01 12:57:31
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https://hk.answers.yahoo.com/question/index?qid=20091230025105AAf7WC9