✔ 最佳答案
Q1 2(x+2a)^2 - a(x+2a) - a^2 = 0
Let y be x+2a :
2y^2 - ay - a^2 = 0
(2y + a)(y - a) = 0
y = - a/2 or y = a
x+2a = -a/2 or x+2a = a
x = -a/2 - 2a =-5a/2
or x = a - 2a = - a
Q2 2^(n+4) - 3(2^(n+3)) ] / 2^(n+2)
= (2^n) [ 2^4 - 3(2^3) ] / [(2^n)(2^2)]
= (16 - 24) / 4
= - 2
Q3 y^2 - 13y + 36
= (y - 4)(y - 9)
x - 13√x + 36 = 0
Let y = √x :
(√x - 4)(√x - 9) = 0
√x = 4 or √x = 9
x = 16 or x = 81