簡單數學問題兩條

2009-12-30 7:21 am
簡單數學問題
x^2-10x-4y2-12y+16

4x^3-39xy2+35y3
更新1:

4x^3-39xy^2+35y^3

回答 (4)

2009-12-30 7:30 am
✔ 最佳答案
x^2 - 10x - 4y2 - 12y + 16
= x^2 - 10x + 25 - 4y^2 - 12y - 9
= (x - 5)^2 - (2y + 3)^2
= (x - 5 + 2y + 3)(x - 5 - 2y - 3)
= (x + 2y - 2)(x - 2y - 8)
4x^3 - 39xy^2 + 35y^3
= 4x^3 - 4xy^2 - 35xy^2 + 35y^3
= 4x(x^2 - y^2) - 35y^2(x - y)
= 4x(x - y)(x + y) - 35y^2(x - y)
= (x - y)(4x^2 + 4xy - 35y^2)
= (x - y)(4x^2 - 10xy + 14xy - 35y^2)
= (x - y)[2x(2x - 5y) + 7y(2x - 5y)]
= (x - y)(2x + 7y)(2x - 5y)
2009-12-31 3:02 am
2009-12-30 8:24 am
x^2 - 10x - 4y2 - 12y + 16



= x^2 - 10x + 25 - 4y^2 - 12y - 9



= (x - 5)^2 - (2y + 3)^2



= (x - 5 + 2y + 3)(x - 5 - 2y - 3)



= (x + 2y - 2)(x - 2y - 8)



4x^3 - 39xy^2 + 35y^3



= 4x^3 - 4xy^2 - 35xy^2 + 35y^3



= 4x(x^2 - y^2) - 35y^2(x - y)



= 4x(x - y)(x + y) - 35y^2(x - y)



= (x - y)(4x^2 + 4xy - 35y^2)



= (x - y)(4x^2 - 10xy + 14xy - 35y^2)



= (x - y)[2x(2x - 5y) + 7y(2x - 5y)]



= (x - y)(2x + 7y)(2x - 5y)


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