ㄧ題簡單留數問題~~~
回答 (3)
2009-12-30 9:39 am
✔ 最佳答案
sinhz=z+z^3/3!+z^5/5!+...1/(1-z^2)=1+z^2+z^4+z^6+...
so, sinhz/(1-z^2)=(z+z^3/6+...)(1+z^2+z^4+...)
=z+(7/6)z^3+...(higher order than z^4)
so, residue of sinhz/[z^4(1-z^2)] at pole z=0 is 7/6
2009-12-29 9:47 am
恩...
因為解別人的發問者會看有錯可以切磋
可是自己解只有自己看
因為解別人的發問者會看有錯可以切磋
可是自己解只有自己看
2009-12-29 6:13 am
收錄日期: 2021-04-30 13:54:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091228000010KK07458