Factorise: 2x^2+3x-2?
回答 (5)
✔ 最佳答案
2x^2 + 3x - 2
= 2x^2 + 4x - x - 2
= (2x^2 + 4x) - (x + 2)
= 2x(x + 2) - 1(x + 2)
= (x + 2)(2x - 1)
2x^2+3x-2 find factors of -2 which will give you a +3 for the middle term and a -2 for the constant
(2x-1)(x+2)
2x^2 + 3x - 2
= 2x^2 + 4x - x - 2
= (2x^2 + 4x) - (x + 2)
= 2x(x + 2) - 1(x + 2)
= (x + 2)(2x - 1)
Factors (2x -1)(x + 2) = 2x^2 +3x -2
收錄日期: 2021-05-01 12:56:44
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