ABCD為一長方形,E,F,G,H為四邊上的以點而且EF//DB//GH.
AF=FB ,,HC=2BH 求AEF+GHC的面積
A----------------F-----------------B
I .........../.........../. .........I
I ...../......... /............/... I H
E I../........ /.. ..... / ............I
I ...../ ...... /.. ................ I
D I-------G-------------------------C
1985年MC不識
2009-12-26 12:21 am
回答 (1)
2009-12-26 1:07 am
✔ 最佳答案
由EF//DB//GH,得△AEF ~ △ ADB = △DBC ~ △GHCAB = 2AF ,
△ADB : △AEF = (2 : 1)^2
△ADB / 4 = △AEF
BC : HC = 3 : 2 ,
△DBC : △GHC = (3 : 2)^2
4△DBC / 9 = △GHC
△AEF+△GHC = △ADB /4 + 4△DBC /9
= (1/2) ABCD /4 + 4 (1/2)ABCD /9
= (1/8 + 2/9)ABCD
= (25/72)ABCD
收錄日期: 2021-04-21 22:05:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091225000051KK00831