a. Factorize a^2-8ab+16b^2
b. Hence, factorize x^4 - 8x^2y^2+16y^4
With Full Step, thx
Maths question
2009-12-24 6:49 pm
回答 (2)
2009-12-24 7:48 pm
✔ 最佳答案
a. a^2-8ab+16b^2= (a)^2-2(a)(4b)+(4b)^2
= (a-4b)^2
b. x^4-8x^2y^2+16y^4
Let a be x^2 and b be y^2
then,
x^4-8x^2y^2+16y^4
=a^2-8ab+16b^2
Using the result in(a):
a^2-8ab+16b^2
=(a-4b)^2
Substitute a=x^2 and b=y^2 into (a-4b)
x^2-4y^2
=(x)^2-(2y)^2
=(x+2y)(x-2y)
thus,
x^4-8x^2y^2+16y^4
=((x+2y)(x-2y))^2
2009-12-24 6:56 pm
a. a^2-8ab+16b^2
= a^2 - 2(a)(4b) + (4b)^2
= (a-4b)^2
b.
let a = x^2, b = y^2
x^4 - 8x^2y^2+16y^4
= a^2-8ab+16b^2
= (a-4b)^2
= (x^2 - 4y^2)^2
= [x^2 - (2y)^2]^2
= [(x-2y)(x+2y)]^2
= a^2 - 2(a)(4b) + (4b)^2
= (a-4b)^2
b.
let a = x^2, b = y^2
x^4 - 8x^2y^2+16y^4
= a^2-8ab+16b^2
= (a-4b)^2
= (x^2 - 4y^2)^2
= [x^2 - (2y)^2]^2
= [(x-2y)(x+2y)]^2
收錄日期: 2021-04-13 16:59:57
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