a + 8 – 2(a – 12) > 0 inequality?

a + 8 - 2(a - 12) > 0
a + 8 - 2(a) + 2(12) > 0
a + 8 - 2a + 24 > 0
a - 2a > -8 - 24
-a > -32
a < -32/(-1)
a < 32

1. Distribute the -2 to (a-12) ===> a+ 8 -2a +24 >0

2. Then put subtract/add both sides ===> a -2a > -24 -8
===> a -2a > -32

3. Add like terms (1a - 2a = -1a)
===> -1a> -32

4. Divide both sides by the coefficient to get "a" alone. ====> a< 32
(When u divide by a negative number-negative 1-, the greater than/less than sign, will change positions)

5. Check ur work:

32+ 8-2 (32-12) >0
40 - 2 (20) >0
40 - 40 >0
0>0

So... a MUST be LESS THAN 32, NOT exactly 32, cuz it will equal to zero!!!

PS: MULTIPLICATION ALWAYS COMES FIRST!!!

PSS: anything higher than 32, will get a number smaller than zero.

just expand it a + 8 - 2(a-12) = a+8-2a +24 = a-2a +8+24 = -a+30 > 0
adding -a to both sides we get a<30

it is inequality a<16

Inequalities are like equations so do the same as you would with an equation and treat the > sign like a =.
Get rid of brackets
a + 8 - 2a + 24 > 0
Simplify
-a + 32 > 0
Move the number over the other side and change sign
-a > - 32
Negate the whole thing, (or times the whole thing by -1.) to get positive a and don't forget to switch the sign when you do this bit.
a < 32
:-)
(It's not < 16)_

expand brackets

a + 8 -2a +24> 0

combine like terms.

-a + 32 > 0

Move 32 across the sign by subtracting it from both sides.

-a> -32

Divide both sides by -1 to isolate 'a'.

a> 32

Therefore the value of a is a number that is greater than 32.

a - 8 - 2a + 24 > 0

16 > a

a < 16