Can someone tell me what x^2 - x - 6 Divided by x^2 - 4 equals?

x^2 - x - 6
---------------
.x^2 - 4

...(x+2)(x-3)
=---------------- cancel x+2
...(x+2)(x-2)

....x-3
=--------- answer//
....x-2

(x² – x – 6) / (x² – 4) = ((x + 2)(x – 3)) / ((x + 2)(x – 2))
............................. = ((x – 3)) / ((x – 2))
............................. = (x – 3) / (x – 2)

( x - 3 ) ( x + 2 )
-------------------------
( x - 2 ) ( x + 2 )

x - 3
----------
x - 2

First factorise each expression separately

x^2 -x - 6 = [x - 3][ x + 2]

x^2 - 4 = [ x+2][x -2]

[x + 2] cancels

Answer = [x - 3] / [x - 2]

a million) For possibilities, convert it to a decimal and multiply. 30%=0.3, so 0.3x45 is 13.5 (in basic terms multiply 40 5 by ability of three then divide by ability of 10). yet because of the fact that is 30% OFF, it is 40 5-13.5, that's 31.5. 2) An inverse is in basic terms the fraction flipped, so the inverse of three/4 is 4/3. The inverse of five/8 is 8/5. 3) comparable because of the fact the 1st: 37.5x2=seventy 5, seventy 5/10= 7.5 ... wallah 4) to locate the slope remember (x1,y1) (x2, y2). Now remember this equation and plug in the corresponding numbers: y2-y1 / x2-x1 (considering the fact that slope is upward thrust over run, and y is upward thrust and x is administered). So on your case, that is -2-5 / 3--2, that's -2-5 / 3+2, that's -7/5 5) Make it a fragment equality: a million.5 / 2 hundred = 6 / ? , multiply the diagonals (it seems greater advantageous in case you write it down, 2 hundred and six are diagonal from eachother) 200x6=1200, then divide by ability of the different extensive variety: a million.5, 1200/a million.5 = 800. With this undertaking however, that is probably much less complicated to do it like this: you elevated a million.5 by ability of four to get 6, so multiply 2 hundred by ability of four to get your answer: 800. i'm hoping this helps :) (btw, your instructor could SUCK)

For a problem like this, you could use long division, or you could choose to factor. In this instance, factoring seems to be the obvious choice.

x^2-x-6 can be factored to (x-3)(x+2)

x^2-4 can be factored to (x-2)(x+2)

Divide [(x-3)(x+2)]/[(x-2)(x+2)], and youll realize the (x+2) factor drops out in the denominator and numerator.

You are left with (x-3)/(x-2).

Your answer is (x-3)/(x-2)

i dont know . can be anything i guess., but they do have a common factor,
x2-x-6 = (x+2)(x-3) and x^2-4 = (x-2)(x+2) , so the common term will cancel out and you get

(x-3) / (x-2)

x^2 - x - 6 = (x - 3)(x + 2)
x^2 - 4 = (x - 2)(x + 2)

(x^2 - x - 6) / (x^2 - 4) = (x - 3) / (x - 2)

(x^2 - x - 6)/(x^2 - 4)
= (x^2 + 2x - 3x - 6)/(x^2 - 2^2)
= [(x^2 + 2x) - (3x + 6)]/[(x + 2)(x - 2)]
= [x(x + 2) - 3(x + 2)]/[(x + 2)(x - 2)]
= [(x + 2)(x - 3)]/[(x + 2)(x - 2)]
= (x - 3)/(x - 2)

(x-3)/(x+2)