maths questions. how to simplify this?

First recognize that the denominator may be rewritten

4^(2n) = (16^n) = (2^n)(8^n)

Then cancel 8^n from both the numerator and the denominator

63(8^n)/(16^n)

= 63 / (2^n)

(63 * 8^n) / (4^2n) Simplify.

(63 * 8^n) / (16^n) The 8^n / 16^n = 1 / 2^n

Answer: 63 / 2^n or (63 * 2^-n)

(63 * 8^n)/[4^(2n)]
= (63 * 8^n)/(16^n)
= 63 * (8^n)/(16^n)
= 63 * (8/16)^n
= 63 * (1/2)^n
= 63 * 1/(2^n)
= 63/(2^n)

63*8^n / 4^2n

= 63 * (2^3)^n / (2^2)^2n

= 63 * 2^3n / 2 ^4n

= 63 /2 ^n

63 ( 8^n )
----------------
4 (2^n )

63 ( 2^n) ( 4^n )
--------------------------
4 ( 2^n )

63 [ 4^(n - 1) ]