I need help factoring the polynomials?

a)
36x^2 - 49y^2
= (6x)^2 - (7y)^2
= (6x + 7y)(6x - 7y)

b)
4xy^2 - 7y
= y(4xy - 7)

c)
x^2 - 5x - 24
= x^2 + 3x - 8x - 24
= (x^2 + 3x) - (8x + 24)
= x(x + 3) - 8(x + 3)
= (x + 3)(x - 8)

d)
3x^2 + 14x - 24
= 3x^2 + 18x - 4x - 24
= (3x^2 + 18x) - (4x + 24)
= 3x(x + 6) - 4(x + 6)
= (x + 6)(3x - 4)

e)
8ax + 20a + 6bx + 15b
= (8ax + 20a) + (6bx + 15b)
= 4a(2x + 5) + 3b(2x + 5)
= (2x + 5)(4a + 3b)

f)
3x^3 + 18x^2 - 48x
= 3x(x^2 + 6x - 16)
= 3x(x^2 + 8x - 2x - 16)
= 3x[(x^2 + 8x) - (2x + 16)]
= 3x[x(x + 8) - 2(x + 8)]
= 3x(x + 8)(x - 2)

a.) 36x^2 - 49y^2=(6x+7y)(6x-7y) answer//

b.) 4xy^2 - 7y =y(4xy-7) answer//

c.) x^2 - 5x - 24 =(x+3)(x-8) answer//

d.) 3x^2 + 14x - 24 = (3x-4)(x+6) answer//

e.) 8ax + 20a + 6bx + 15b
=4a(2x+5)+3b(2x+5)
=(4a+3b)(2x+5) answer//

f.) 3x^3 + 18x^2 - 48x
=3x(x^2+6x-16)
=3x(x-2)(x+8) answer//

36x^2-49y^2)= (6x-7y)(6x+7y)

y(4x^2-7)

x^2-5x-24 (x-8)(x+3)

3x^2+14x-24 (3x-4)(x+6)

8ax+20a+6bx+15b 4a(2x+5)+3b(2x+3) 4a+3b 2x+3

3x^3+18x^2-48x 3x(x^2+6x-16)(3(x+8)(x-2)

a) (6x+7y) (6X-7y)
b) y(4x-7y)
c)x^2 -8x +3x -24 = x(x-8)+3(x-8)= (x-8)(x+3)
d)3x^2+18x-4x-24= (3x-4)(x+6)
e) 4a(2x+5)+ 3b(2x+5)= (4a+3b) (2x+5)
f) 3x(x^2+ 6X-16)= 3x(x-2)(x+8)

a) (6x)^2 -- (7y)^2 = (6x+7y)(6x--7y) [recall a^2 --b^2 = (a+b)(a--b)]
b) y(4xy--7) [just y as common]
c) (x--8)(x+3)[--24 factorized as --8,3 since sum gives --5 and product is --24]
d) (3x--4)(x+6) [--3*24 get factorized as +18, --6 so sum gives +14]
e) 4a(2x+5)+3b(2x+5) = (2x+5)(4a+3b) [as we take (2x+5) as common]
f) 3x(x^2+6x--16) = 3x(x+8)(x--2) [hope you understand by this time]