能否詳解
3^(n+4)-3(n+2)
=8x3^(n+2)
如何求得答案?
指數問題..請解答...
2009-12-20 4:19 am
回答 (1)
2009-12-20 4:44 am
✔ 最佳答案
重寫 3^(n+4)-3^(n+2)= (3^2)[3^(n+2)] - 3^(n+2)
=(9)3^(n+2) - 3^(n+2)
=[9-1](3^(n+2))
=(8)[3^(n+2)]
收錄日期: 2021-04-13 17:00:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091219000051KK01209