Factorise 8y^2-10y-3?

8y² - 10y - 3 = 0 Reduce 8y² to y²
y² - 5/4y = 3/8 Split the coefficient - 5/4 into 2
y² - 5/8y = 3/8 + (- 5/8)² Expand/simplify (- 5/8)²
y² - 5/8y = 24/64 + 25/64 Simplify
(y - 5/8)² = 49/64 Take the square root of both sides
y - 5/8 = ± 7/8 Starting here you may determine the factors

= y - 5/8 - 7/8, = y - 12/8, = y - 3/2, = 2y - 3
= y - 5/8 + 7/8, = y + 2/8, = y + 1/4, = 4y + 1

Answer: (2y - 3)(4y + 1) are the factors.

Use the basic formula

a = 8
b = -10
c = -3

y = [b +/- sqrt[b^2 - 4ac]
y = [10 +/- sqrt[100 + 96]]/16
y = [10 +/- 14]/16
y = 24/16 or -4/16
y = + 3/2 or - 1/4

so, it's

[y - 3/2][y + 1/4]

And don't forget to put this question to vote cuz there is alot of great answers. Trust me u don't want to put the wrong best answer. The voters will give the best answer for u. Have a great day. Bye.........

8y^2 - 10y - 3
= 8y^2 + 2y - 12y - 3
= (8y^2 + 2y) - (12y + 3)
= 2y(4y + 1) - 3(4y + 1)
= (4y + 1)(2y - 3)

(4y +1) ( 2y -3)

=)

( 4 y + 1 ) ( 2 y - 3 )

Use the formula

a = 8
b = -10
c = -3

x = [10 +/- sqrt[100 + 96]]/16

x = [10 +/- 14]/16

x = 24/16 or -4/16

x = + 3/2 or - 1/4

factors are

[x - 3/2][x + 1/4]

PS SORRY

USED X INSTEAD OF Y

FACTORS ARE

[y - 3/2][y +1/4]

8y^2 - 10y - 3

8y^2 + 2y - 12y - 3

2y( 4y+ 1) -3 (4y + 1)

(2y-3) (4y+1)

use square equation to get:

y1=-3/2

y2=1/4

so you get

(y+3/2)(y-1/4)