Can someone factorise this....2p(squared)-18?

= 2( p ² - 9 )

= 2( p - 3 )( p + 3 )

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2 ( p ² - 9 )

2 ( p - 3 ) ( p + 3 )

2(p^2-9)=2(p^2-3^2)=2(p-3)(p+3)

2p^2 - 18
= 2(p^2 - 9)
= 2(p^2 - 3^2)
= 2(p + 3)(p - 3)

Take 2 as a common factor:

2 ( p^2 -9)

Then use this rule: a^2 -b^2 = (a-b) (a+b)

2 (p-3)(p+3)

Quiet easy =)

2xPx itself - 18