4.2g無水碳酸氫鈉,加入含硫酸4.41g的100mL溶液中,試計算:
1).標準狀況下產生的二氧化碳的體積;
2).反應後溶液中硫酸的物質的量的濃度(設體積不變).
化學計算題一問?(趕!!!!)
2009-12-12 7:43 am
回答 (1)
2009-12-12 5:46 pm
✔ 最佳答案
1)Equation:2NaHCO3+H2SO4----------->Na2SO4+2H2O+2CO2no. of mole of NaHCO3=4.2/(23+1+12+16x3)=0.05 mol
no. of mole of H2SO4=4.41/(1x2+32.1+16x4)=0.045 mol
As 1/2 x no. of mole of NaHCO3<no. of mole of H2SO4
so, NaHCO3 is limited reactant.
as 2 mole NaHCO3 produce 2 mole CO2
the volume of CO2 produced=0.05x24=1.2 dm3
2)no. of mole of H2SO4 remained =0.045-0.05/2=0.02 mol
Concentration after reaction =0.02/0.1=0.2mol/dm3(0.2M)
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