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回答 (2)
2009-12-12 3:41 am
✔ 最佳答案
70(3-x)^2-11(3-x)-3=(7(3-x)+1)(10(3-x)-3)
=(21-7x+1)(30-10x-3)
=(22-7x)(27-10x)
=(7x - 22)(10x - 27)
參考: 052
2009-12-12 6:39 am
Let y be (3-x)
70(3-x)^2 -11(3-x)-3
=70y^2-11y-3
=(7y+1)(10y-3)
=(21-7x+1)(30-10x-3)
=(22-7x)(27-10x)
=(7x-22)(10x-27)
70(3-x)^2 -11(3-x)-3
=70y^2-11y-3
=(7y+1)(10y-3)
=(21-7x+1)(30-10x-3)
=(22-7x)(27-10x)
=(7x-22)(10x-27)
收錄日期: 2021-04-21 22:07:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091211000051KK01199