畢氏定理問題x 1

AC^2 + (4/3AC)^2 = 7.5^2
AC^2 + (4/3AC)^2 = 56.25
AC^2 + (16/9)AC^2 = 56.25
25.9AC^2 = 56.25
AC^2 = 20.25
AC = 4.5

2009-12-10 21:33:19 補充：
AC^2 + (4/3AC)^2 = 7.5^2
AC^2 + (4/3AC)^2 = 56.25
AC^2 + (16/9)AC^2 = 56.25
25/9AC^2 = 56.25
AC^2 = 20.25
AC = 4.5
上面的錯了,這樣才對

2009-12-10 21:34:46 補充：
AC^2 + (4/3AC)^2 = 7.5^2
AC^2 + (4/3AC)^2 = 56.25
AC^2 + (16/9)AC^2 = 56.25
(25/9)AC^2 = 56.25
AC^2 = 20.25
AC = 4.5
真正好了.用這個

最簡單方法


AC^2 + (4/3AC)^2 = 7.5^2
AC^2+ (4/3)^2xAC^2=7.5^2



抽個ac^2出來
AC^2x(1+(4/3)^2)=7.5^2

AC=開方(7.5^2)/(1+(4/3)^2)

=4.5

2009-12-11 14:11:06 補充：
你個答案好似錯wor,應該係正負4.5

2009-12-11 14:13:22 補充：
AC^2=(7.5^2)/(1+(4/3)^2)

因為ac^2等於一舊正數，咁ac=-4.5,ac^2都係等於一舊正數