F.1數學喔=]]]]【20分】

(a)3(2-d)=-2d
∴6=-2d-3d ----->6=-2d+3d
(b) 4(3m-1)=2m+4
∴3m-1=m+1 ----->3m-1=1/(2m)+1
(c) 2n+3=4-n
∴2n+n=4+3 ----->2n+n=4-3

解下列方程
＊可以吾寫步驟,但有埋更好=]]]
(a)11r=8r-6
3r=-6
r=-2

(b)2(x+4)+3x=3
2x+8+3x=3
5x=-5
x=-1

(c)7(3p-4)=5(3p-5)+1
21p-28=15p-25+1
6p=3+1
p=2/3

A,3(2-d)=-2d
∴6-3d=-2d
6=-2d+3d
B, 4(3m-1)=2m+4
∴12m-4=2m+4
-4+4=2m-12m
C,2n+3=4-n
∴ 3+4=-n+2n
方程:
(a)11r=8r-6
-6=8r-11r
-6=-3r
2=r
b)2(x+4)+3x=3
2x+8+3x=3
5x+8-8=3-8
5x=-5
x=-1
(c)7(3p-4)=5(3p-5)+1
21p-28=15p-25+1
21p-15p=-24+28
6p=4
p=2/3(即3分之3)
我是第一個答的
請比分我xD

6=-2d-3d =6=-2d/3d
3m-1=m+1=3n-1=f+1
2n+n=4+3=2m+m=4+3=2m

紅色
(a) 6=-2d+3d
(b) 12m-4=2m+4
(c) 2n+n=4-3

(a)11r=8r-6
3r=-6
r=-2
(b)2(x+4)+3x=3
2x+8+3x=3
x=-1
(c) 7(3p-4)=5(3p-5)+1
21p-28=15p-25+1
p=2/3