急! 中四數學thx :D

2009-12-08 5:48 am
Expand the following expression in ascendnig powers of x as fair as the term in x^3

1. e^3x - 2e^2x
2. 1+x+x^2 / e^2x

要STEPS THX!
十萬火急急呀...明日交功課!

回答 (1)

2009-12-08 6:00 am
✔ 最佳答案

e^x = 1 + x + x^2/2! + x^3/3! + ...
(1) e^3x - 2e^2x
= [1 + 3x + (3x)^2/2! + (3x)^3/3! + ...] - 2[1 + 2x + (2x)^2/2! + (2x)^3/3! + ...]
= 1 + 3x + (9/2)x^2 + (9/2)x^3 + ... - 2 - 4x - 4x^2 - (8/3)x^3 - ...
= -1 - x + (1/2)x^2 + (11/6)x^3 + ...
(2) (1 + x + x^2) / (e^2x)
= (1 + x + x^2)[e^(-2x)]
= (1 + x + x^2)[1 - 2x + 2x^2 - (4/3)x^3...]
= 1 - 2x + 2x^2 - (4/3)x^3 ... + x - 2x^2 + 2x^3... + x^2 - 2x^3...
= 1 - x + x^2 - (4/3)x^3


收錄日期: 2021-04-23 23:20:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20091207000051KK01558

檢視 Wayback Machine 備份